C:\Users\maria sapuppo\Desktop\Pitagora\Esercizi\dimostrazioni geogebra\Geogebra\17La generalizzazione di Quang H.Trangeogebra-export

A

C

B

T

E

H

K

G

T_2

F

T_1

D

Avanti

Indietro

Reset

T_4

T_3

γ

Muovi lo slider γ per modificare
il triangolo ABC. Nel caso in cui
γ=90° il triangolo ABC diventa 
rettangolo e ritroviamo la relazione
pitagorica.

I triangoli T, T_1, T_2 sono triangoli equilateri

γ: 76°
M = (13, 2)
N = (15, 6)
M' = Rotate(M, γ, N)
γ_{1} = Angle(M, N, M')
i_1 = Segment(N, M)
j_1 = Segment(N, M')
O = (11, 2)
P = (17, 2)
k_1 = Line(O, P)
l_1 = Ray(N, M')
R = Intersect(l_1, k_1)
m_1 = Segment(M, R)
n_1 = Segment(R, N)
poli4, p_1, q_1, r_1, S = Polygon(R, M, 3)
s_1 = OrthogonalLine(N, m_1)
t_1 = OrthogonalLine(M, j_1)
a_1 = OrthogonalLine(R, i_1)
T = Intersect(s_1, t_1)
V = Intersect(t_1, j_1)
W = Intersect(s_1, m_1)
b_1 = Segment(N, W)
e_1 = Segment(M, V)
n_2 = OrthogonalLine(R, i_1)
B_1 = Intersect(n_2, i_1)
p_2 = Segment(B_1, R)
q_2 = Segment(N, T)
r_2 = Segment(M, T)
f_2 = Segment(M, B_1)
g_2 = Segment(V, R)
poli5, h_2, i_2, j_2, U = Polygon(M, B_1, 3)
poli6, k_2, a_2, b_2, Z = Polygon(V, R, 3)
c_2 = Segment(U, N)
d_2 = Segment(N, Z)
a: 0
b = If(false, 10)
c = If(false, 10)
d = If(false, 10)
e = If(false, 10)
f = If(false, 10)
g = If(false, 10)
h = If(false, 10)
minimo = 0 (slider from -5 to 5)
t1, n, m, r = Polygon(M, R, N)
t2, n_3, u, i = Polygon(U, B_1, N)
t3, z_1, n_4, v = Polygon(N, V, Z)
α: γ
testo1: "A(T)=A(T_1+T_3)+A(T_2+T_4)=
" + poli4 + "=(" + poli6 + "+" + t3 + ")+(" + poli5 + "+" + t2 + ")"
δ = Angle(N, W, M)
ε = Angle(R, B_1, N)
ζ = Angle(M, V, R)
massimo = 11 (slider from -5 to 20)
β: γ